我有以下URL：
http://example.com/?s=&cp_state=0&scat=16&sa=search&refine_search=yes

此代码位于search.php:

<?php                  
$searchTxt = trim( strip_tags( esc_attr( get_search_query() ) ) );
$state_append = \'\';
$state = $_GET[\'cp_state\'];
if($state != \'0\') 
    $state_append = __(\'\', APP_TD).\' \' . $state;

$cat_id =  $_GET[\'scat\'];
if ( $searchTxt ==  __(\'What are you looking for? \', APP_TD) || $searchTxt == __(\'[All]\', APP_TD) ) 
    $searchTxt = \'*\';   

if($searchTxt){
    if($searchTxt == \'*\') {
        if($cat = get_term_by(\'id\', $cat_id, \'ad_cat\')) {
            printf( __("Ads %s %s ", APP_TD), $cat->name, $state_append, $wp_query->found_posts ); 
        } else {
            printf( __("Ads %s ", APP_TD), $state_append, $wp_query->found_posts ); 
        }
    } else {
        printf( __("What are you looking for? \'%s\' %s ", APP_TD), $searchTxt, $state_append,      $wp_query->found_posts ); 
    }
}else{
    $searchTxt = trim( strip_tags( esc_attr( get_search_query() ) ) );
    printf( __("What are you looking for? \'%s\' %s ", APP_TD), $searchTxt, $state_append,      $wp_query->found_posts );
}
echo $cat_id;
?>

我想获取URL的类别名称。我尝试使用echo $cat_id, 但它给我的是编号，而不是类别的名称。

如何“回显”类别的名称而不是编号？

$myterm = get_term_by(\'id\', $cat_id, \'category\');
if ( $myterm ) {
    echo $myterm->name;
}