$locations = get_the_terms( $post_id, \'location\' );
foreach ( $locations as $location ) {
echo \'<a href="\'.site_url().\'/location/\'.$location->slug.\'">\'. $location->name .\'</a>\';
break;
}
如果有父分类法，如何获取所有父分类法？
例如：
当前代码输出London 在前端。
需要输出的内容Europe > England > London.
我设法挖掘或尝试的是get_the_terms() 也有parent 可以用作$location->parent. 这个只有ID属性，我并没有设法从中挤出名称或名称。此外，如果它有父对象，也无法使用它来检索它的父对象。
<小时>
Update after some experimenting:
//Parent
if( $location->parent != "" ) {
$location_parent_id = $location->parent;
$location_parent = get_term_by( \'id\', $location_parent_id, \'location\' );
echo $location_parent->name; //Here it is
}
//If I need parent of parent
if( $location_parent->parent != "" ) {
$location_parent_parent_id = $location_parent->parent;
$location_parent_parent = get_term_by( \'id\', $location_parent_parent_id, \'location\' );
echo $location_parent_parent->name; //Here it is
}
//etc
Is this very grazy approach?
最合适的回答,由SO网友:s_ha_dum 整理而成
你想要的get_ancestors(). 这很粗糙但是。。。
$locations = get_the_terms( $post->ID, \'category\' );
// var_dump($locations);
$pat = \'<a href="\'.site_url().\'/location/%s">%s</a>\';
foreach ( $locations as $location ) {
printf($pat,$location->slug,$location->name);
$anc = get_ancestors($location->term_id,\'category\');
if (!empty($anc)) {
foreach ($anc as $term) {
$t = get_term_by( \'term_id\', $term, \'category\');
printf($pat,$t->slug,$t->name);
}
}
break;
}
SO网友:Juan Rangel
听起来您想以层次结构格式显示分类法？这是我最近做的事情。试试这样的
// Get all taxonomies that do not have a parent/top level taxonomies
$parents = get_terms( $taxonomy, array( \'hide_empty\' => true, \'parent\' => 0 ) );
foreach ( $parents as $parent ) {
echo $parent->name . \': \';
$child_terms = array();
// Get all post terms for this post and use the parent ID to grab the children
$children = wp_get_post_terms( get_the_ID(), $taxonomy, array( \'hide_empty\' => true, \'parent\' => $parent->term_id ) );
foreach ( $children as $child ) {
// build a link to the children taxonomy archive
$child_terms[] = sprintf( \'<a href="%s">%s</a>\', get_term_link($child, $taxonomy), $child->name );
}
echo implode( \', \', $child_terms) . \'<br>\';
}
