If post author role is X

简化我当前显示特色帖子的方式，当一篇帖子由正式成员提交时，会向帖子添加一个post\\u meta值，然后以不同的样式显示。

但是我想根据帖子作者，用户角色来做这件事。

因此，如果提交帖子的用户是“full\\u成员”，那么他们的帖子将自动显示，而无需查询post\\u meta。

我在归档模板循环中尝试过类似的方法，只是在包装div中添加了一个“featured listing”类，但我认为我没有正确地看待它。

 <?php $user = wp_get_current_user();
if ( in_array( \'full_member\', (array) $user->roles ) ) { ?>

featured-listing

<?php } ?>

EDIT

第1部分已使用Nathan对课堂问题的原始答案解决，自那以后，他的答案已经扩展，这对我不起作用，因此我将有效的解决方案粘贴在下面：

//* If the post author is a full member, they get a featured listing
function which_class() {
  return post_author_role_in( \'full_member\' ) ? \'featured-listing\' : \'regular-listing\';
}

//* Determine if the post author is in the $role
function post_author_role_in( $role ) {
  return in_the_loop() ? user_role_in( get_the_author_meta( \'ID\' ), $role ) : false;
}

//* Determine if the $user_id is in the $role
function user_role_in( $user_id, $role ) {
  return in_array( $role, ( new WP_User( $user_id ) )->roles );
}

Part 2 However I still need a solution for

Id仍然希望使用条件来完全隐藏模板中的某些元素，是否有IF condition 比如说IF post author is in X role, display this, else display this. ?
请告知：）

//gets the ID of the post $post_id = get_queried_object_id(); //gets the ID of the author using the ID of the post $author_ID = get_post_field( \'post_author\', $post_id ); //Gets all the data of the author, using the ID $authorData = get_userdata( $author_ID ); //checks if the author has the role of \'subscriber\' if (in_array( \'subscriber\', $authorData->roles)): //show the content for subscriber role else: //show the content for every other role endif;

//* Return whether the post author is a member //* This function will only work in the loop function is_member() { return post_author_role_in( \'full_member\' ); } //* If the post author is a full member, they get a featured listing //* This function will only work in the loop function which_class() { return is_member() ? \'featured-listing\' : \'regular-listing\'; } //* Determine if the post author is in the $role function post_author_role_in( $role ) { return in_the_loop() ? user_role_in( get_the_author_id(), $role ) : false; } //* Get the author ID function get_the_author_id() { return get_the_author_meta( \'ID\' ); } //* Determine if the $user_id is in the $role function user_role_in( $user_id, $role ) { return in_array( $role, ( new WP_User( $user_id ) )->roles ); }

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