我发现这段代码可以获取当前用户的评级帖子列表,但它不起作用。插件WP评级1.85/WP 4.9.7
有什么想法吗?
<?php
global $wpdb, $current_user;
$userranking = $wpdb->get_results( " SELECT * FROM wp_ratings WHERE rating_userid=$current_user->ID ");
if($userranking) {
foreach ( $userranking as $userranking ) {
echo "<li><a class=\'rankedposttitle\' href=\'".get_permalink($userranking->rating_postid). "\'>" .get_the_title($userranking->rating_postid). "</a></li>";
}
}
?>
我也尝试过:<?php
$sql = "SELECT * FROM wp_ratings WHERE rating_userid LIKE \'$current_user- >ID\'";
$result = $wpdb->get_results($sql) or die(mysql_error());
foreach( $results as $result ) {
echo $result->name;
}
?>
不起作用,我所有的选民都是wordpress的支持者,应该登录投票。谢谢