我需要获取类别url,以便将其放入元代码段中。现在,span内的输出是带有url的标记。我只需要获取不带标记的url,并将其放入$cat\\u display中。我尝试使用2个选项,但会看到一个错误:注意:尝试获取非对象的属性
// Get post category info
$category = get_the_category();
if(!empty($category)) {
// Get last category post is in
$last_category = $category[count($category) - 1];
// Get parent any categories and create array
$get_cat_parents = rtrim(get_category_parents($last_category->term_id, true, \',\'),\',\');
$cat_parents = explode(\',\',$get_cat_parents);
//$category_link = get_category_link( $category_id );
$cat_parents_url = get_category_link($cat_parents->term_id);
// Loop through parent categories and store in variable $cat_display
$cat_display = \'\';
foreach($cat_parents as $parents) {
$cat_display .= \'<li class="item-cat" itemprop="itemListElement" itemscope itemtype="http://schema.org/ListItem"><span itemprop="item"><span itemprop="name">\'.$parents .\'</span></span><meta itemprop="position" content="\'. $counter++ .\'" /></li>\';
$cat_display .= \'<li class="separator"> \' . $separator . \' </li>\';
}
}