您可以在任何WordPress页面/模板上使用此选项。

<?php if ( is_user_logged_in() ) : ?>
    //Code for only logged in users
<?php endif; ?>

最简单的解决方案：您可以使用纯css，如下所示：

.button-class {display: none;}
.logged-in .button-class {display: block;}

For me only works

/* show blog button only if logged in */
li.button-class {
    visibility: hidden !important;
    display: none !important;
}
.logged-in li.button-class { 
    visibility: visible !important;
    display: inline-block !important;
}

Try this

 add_action( \'loop_start\',      \'your_function\' );
 function your_function() {

 if ( is_user_logged_in() ) {
echo \'<li id="text-2" class="hide">\';
} else {
echo \'<li id="text-2">\'; 
}}

这是我使用的：

functions.php （儿童主题）：

add_action(\'shutdown\', function() {
    $final = \'\';
    $levels = ob_get_level();
    for ($i = 0; $i < $levels; $i++)
    {
        $final .= ob_get_clean();
    }
    echo apply_filters(\'final_output\', $final);
}, 0);

add_filter(\'final_output\', function($output) {
  $display1 = \'none\';
  $display2 = \'block\';

  if(is_user_logged_in()) {
    $display1 = \'block\';
    $display2 = \'none\';
  }

  $from = array(\'%display1%\', \'%display2%\');
  $to = array($display1, $display2);
  $output = str_replace($from,$to,$output);

  return $output;
});

CSS:

.for-logged-in-users {
display: %display1%;
}
.for-logged-out-users {
display: %display2%;
}