解决了上述任务,将答案张贴在此处,以便有人可以使用代码
我在函数中添加了此代码。php
function is_user_video_perweek( $reg_days_ago )
{
$currentuser = wp_get_current_user();
return ( isset( $currentuser->data->user_registered ) && strtotime( $currentuser->data->user_registered ) < strtotime( sprintf( \'-%d days\', $reg_days_ago ) ) );
}
然后在页脚中。php我调用了这个函数,并使用javascript示例编写了禁用链接的条件
<?php if( is_user_video_perweek( 84 ) )
{
?>
<script type="text/javascript">
jQuery(".page-id-1572 #allvideos a").css("pointer-events", "auto");
</script>
<?php
}elseif( is_user_video_perweek( 0 ) ){?>
<script type="text/javascript">
jQuery(".page-id-1572 #allvideos a").css("pointer-events", "none");
</script>
<?php } ?>