我想把我的评论结果放入另一个结果中。
我想要这个结果
$args = array(
\'post_id\' =>$post->ID,
\'status\' => \'approve\',
\'type\' => \'review_comment\',
);
$comments = get_comments( $args );
$abb = $comment->comment_content;
$acc = get_comment_meta($comment->comment_ID, COMMENT_TITLE_METAKEY, true);
$add = get_comment_meta($comment->comment_ID, COMMENT_RATING_METAKEY, true);
$aee = get_comment_date( \'d\\/m\\/Y\' );
$aff = get_the_title();
$agg = $comment->comment_author;
$comlist = "review" => [
"@type" => "Review",
"headline" => $acc,
"reviewbody" => $abb,
"datePublished" => $aee,
"itemReviewed" => [
"@type" => "Organization",
"name" => $aff,
],
"author " => [
"@type" => "Person",
"name" => $agg,
],
];
$comlistall = foreach ( $comments as $comment ){
$comlist ;
};
把这个结果放进去。 <?php
$rtitlez = get_the_title();
$rimgz = get_the_post_thumbnail_url(get_the_ID(), \'full\');
$rvaluez = get_post_meta($post->ID, \'comments_rating_value\', true);
$rcountz = get_post_meta($post->ID, \'comments_rating_count\', true);
$result = [
"@context" => "https://schema.org/",
"@type" => "Organization",
"name" => $rtitlez,
"image" => $rimgz,
"aggregateRating" => [
"@type" => "AggregateRating",
"ratingValue" => $rvaluez,
"bestRating" => "5",
"worstRating" => "1",
"ratingCount" => $rcountz
],
/*I want here $comlistall*/
]
;?>
<script type="application/ld+json"><?php echo json_encode($result); ?></script>
我该怎么做?