检索所需结果的注释属性的正确方法

我正在使用此代码，但无法使其100%正常工作。注释返回与之相关的所有内容，但我只想检索具有所需属性的注释。

<?php

    $args = array(
                    \'post_id\'   =>$post->ID,
                    \'status\'  => \'approve\',
                    \'type\'  => \'wp_review_comment\',
                );
     $comments = get_comments( $args );

    // Create an empty array
    $comlistall = array();

    foreach ( $comments as $comment ){

          $c = [ "review" => [
            "@type" => "Review",
            "headline" => (get_comment_meta($comment->comment_ID, WP_REVIEW_COMMENT_TITLE_METAKEY, true)),
            "reviewbody" => ($comment->comment_content),
            "datePublished" => (get_comment_date( \'d\\/m\\/Y\' )),
            "itemReviewed" => [
                "@type" => "Organization",
                "name" => (get_the_title()),
                ],
            "author " => [
                "@type" => "Person",
                "name" => ($comment->comment_author),
                ],
            "reviewRating"=> [
                "@type" => "Rating",
                "ratingValue" => (get_comment_meta($comment->comment_ID, WP_REVIEW_COMMENT_RATING_METAKEY, true)),
                ],
             "publisher" => [
                 "@type" => "Organization",
                 "name" => "Sitejury",
                 "sameAs" => "https://sitejury.com",
                ],
            ]
        ];  
        $comlistall[] = $c;
    };

$result = [
  "@context" => "https://schema.org/",
  "@type" => "Organization",
  "name" => (get_the_title()),
  "image" => (get_the_post_thumbnail_url(get_the_ID(), \'full\')),
  "aggregateRating" => [
        "@type" => "AggregateRating",
        "bestRating" => "5",
        "worstRating" => "1",
        "ratingValue" => (get_post_meta($post->ID, \'wp_review_comments_rating_value\', true)),
        "ratingCount" => (get_post_meta($post->ID, \'wp_review_comments_rating_count\', true)),
  ],
    $comlistall,
] ;?>                       

<script type="application/ld+json"><?php echo json_encode($result); ?></script>

目前，我的问题是，现在的结果在"0" = [{ 属性我正在努力摆脱"0" = [{ 属性

结果url：https://sitejury.com/review/zzzzzz/

检查结构化数据：https://search.google.com/structured-data/testing-tool/u/0/#url=https%3A%2F%2Fwww.sitejury.com%2Freview%2Fzzzzzz%2F

回拨问题：How to put this result inside that result.

我想要的结果：https://search.google.com/structured-data/testing-tool/u/0/#url=https%3A%2F%2Fwww.sitejabber.com%2Freviews%2Fbillmelater.com

$result = [ "@context" => "https://schema.org/", "@type" => "Organization", "name" => (get_the_title()), "image" => (get_the_post_thumbnail_url(get_the_ID(), \'full\')), "aggregateRating" => [ ... ], \'review\' => $comlistall, // here, a "review" item must exists /* Or something like so: \'review\' => array( array( "@type" => "Review", "headline" => ..., "reviewbody" => ..., ... ), array( "@type" => "Review", "headline" => ..., "reviewbody" => ..., ... ), ... ), */ ];

$c = [ "review" => [ "@type" => "Review", "headline" => (get_comment_meta($comment->comment_ID, WP_REVIEW_COMMENT_TITLE_METAKEY, true)), "reviewbody" => ($comment->comment_content), ... ] ]; $comlistall[] = $c;

Comments.php保留评论日期/时间，但删除日期/时间的#超级链接

我在谷歌上搜索了这个问题，似乎找不到解决方案。。。在评论中，我试图从评论日期/时间中删除超链接，当您将鼠标悬停在评论日期上方时，它会将超链接（示例/#comment-210）链接到以下评论。。。我可以在函数中输入什么。php删除链接，我想保留日期/时间文本。。

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Comments.php保留评论日期/时间，但删除日期/时间的#超级链接