如何在PHP中获取一个块的所有属性？

我正在重写PHP中的核心图像块。一切都很顺利，只是我发现Javascript中该块的所有属性都没有传递给PHP供我使用。

如何覆盖图像块：

    //Override core/image block with render callback
    function override_image_block_output($attributes, $content){
      //Override the image block
      var_dump($attributes);
    }

    function reregister_image_block(){
        register_block_type( \'core/image\', array(
            \'render_callback\' => \'override_image_block_output\',
        ) );
    }

    add_action(\'init\', \'reregister_image_block\');

当我这样做，var\\u转储$attributes, 我只有这些

array(3) { ["id"]=> int(282) ["sizeSlug"]=> string(5) "large" ["linkDestination"]=> string(6) "custom" }

但在Javascript中，您可以通过以下方式查看该块的属性：

const { addFilter } = wp.hooks;
const __ = wp.i18n.__; // The __() for internationalization.
const el = wp.element.createElement; // The wp.element.createElement() function to create elements.
const { RichText } = wp.blockEditor;
const { InnerBlocks } = wp.blockEditor;

const OverrideImageBlock = (element, blockType, attributes) => {
    if ( blockType.name === \'core/image\' ) {
        console.log(attributes);
        return element;
    }

    return element;
};

addFilter(
  "blocks.getSaveElement",
  "custom-blocks/override-core-image-block",
  OverrideImageBlock
);

属性返回以下内容：

如何将“href”从块的属性传递到PHP？为什么有些通过了，但有些最初没有通过？

"url": { "type": "string", "source": "attribute", "selector": "img", "attribute": "src" }, "alt": { "type": "string", "source": "attribute", "selector": "img", "attribute": "alt", "default": "" },

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