当我试图从php shortcode函数获得多个响应时，其Json输出结果很奇怪。在我的php中，
$result[\'success\']=false;
$result[\'string\']=\'You have not uploaded project file, please upload first!\';
echo json_encode($result);
$.post(ajax_object.ajax_url, { //POST request
...............
}, function(data) { //callback
console.log(data);
alert(data);
});
{"success":"true","string":"You have not uploaded project file, please upload first!"}0
如中所述the documentation:
当处理程序完成所有任务时，它需要死亡。如果您正在使用WP_Ajax_Response 或wp\\u send\\u json*函数，这将自动为您处理。如果没有，只需使用WordPresswp_die() 作用
wp_die();
// That\'s all folks!
$result[\'success\'] = false;
$result[\'string\'] = \'You have not uploaded project file, please upload first!\';
echo json_encode( $result );
wp_die();
$result[\'success\'] = false;
$result[\'string\'] = \'You have not uploaded project file, please upload first!\';
wp_send_json( $result );
success 属性设置为false 对于您这样的人：$result = \'You have not uploaded project file, please upload first!\';
wp_send_json_error( $result, 400 );
{
"success": false,
"data": "You have not uploaded project file, please upload first!"
}
我尝试，当单击submit按钮时，用一些值传递ajax请求，然后计算这些值并返回。My Problem : 当我进行自定义Ajax调用时，我从管理Ajax得到400个错误。php。请帮我找出我的错误或最好的方法来做这件事。Ajax Call - footer.php(theme footer) <script> $(function() { $(\"#calc_form\").on(\"submit\", function(e) {